According to Chargaff’s rule, the concentration of guanine approximately equals the concentration of cytosine.

In other words

In other words

The amount of purine = The amount of pyramidine in a given DNA molecule.

[A]+[G]=[C]+[T]

**Adenine (A) is**paired to

**Thymine (T) by 2**hydrogen bonds

**Cytosine (C ) is**paired to

**Guanine (G) by 3**hydrogen bonds

**Genetics Problems: C**

**hargaff's Rule Questions**

Rule 1: The amount of Adenine ~equals the amount of Thymine

The amount of Guanine ~equals the amount of Cytosine

The amount of purine = the amount of pyramidine

Rule 2: The amount of A+T ≠ amount of G+C. This ratio varies among different organisms but same in different tissues of the same organism

**1. A segment of DNA has 120 adenine and 120 cytosine bases. The total number of nucleotides present in the segment is**

a) 60 (b)120 (c) 240 (d) 480

**According to Chargaff rule,**

- Adenine (A) is paired to Thymine (T)
- Cytosine (C ) is paired to Guanine (G)

Here adenine residues =120, cytosine residues = 120

[A]=[T][A= 120]=[T=120][C]=[G][C= 120]=[G=120]

there fore total number of nucleotides = [A] + [T]+ [C]+[G] =

**120 X 4 = 480****Ans:**d) 480

**Enroll Now - Understand
the Basics of rDNA Technology in 2 hours **

**2. In humans, there is approximately 30% adenine. What is the percentage of other nitrogenous bases?**

According to Chargaff’s rule, [A]+[G]=[C]+[T]

[A]+[G]+[C]+[T]=100%

Adenine (A) is paired to Thymine (T), A=T

Cytosine (C ) is paired to Guanine (G), G=C

Here [A]=30% therefore % of [T] is also 30%.

therefore [G]+[C]=100 - 60 = 40 %.

[G]=20% and [C]=20%

##
**Ans. is [A]=30%, [T]=30%,[G]=20%, [C]=20%**

**3. In a DNA sample, the percentage of adenine is 40% and percentage of thymine is 60%. What is your inference?**

According to Chargaff’s rule, Concentration of adenine=concentration of thymine. therefore if [A]=40% then the [T] will also be 40%.

**But this rule rule is applicable only for double stranded DNA molecule.**

The possibility of Adenine=40% and Thymine=60% is only in single stranded DNA molecule.

In the question, the DNA sample referred is a single stranded DNA.

(A+G)/(T+C) in the complementary strand will be (T+C)/(A+G) =10:7 or 10/7 = 1.4285 =

(A+G) / (T+C)= 0.7 or 7/10

A+G =7 (A=4, G=3)

T+C= 10 (T=8, C=2)

complementary strand (T+C)/(A+G) = (8+2)/(4+3) =10/7 = 1.4285 = 1.43

**4. In DNA, guanine is 10%. The content of adenine is**
a) 90% (b) 80% (c) 40% (d) 20% (e) 10%

If guanine=10% as

**guanine will always pair with cytosine**, i.e.cytosine is also 10% then adenine and thymine accounts 80% as**adenine will always pair with thymine.**

**So adenine=40%,**thymine=40%, guanine=10% & cytosine=10%

OR

Cytosine =10%

A+G+C+T=100%

A+10%+10%+T=100%

A+T=100%-20%=80%

A/T=80%/2=40%

**Ans:**40%

**5.**

**If the ratio (A+G)/(T+C) in one strand of DNA is 0.7, what is the same ratio in complementary strand.?**

**Ans:**(A+G) / (T+C)= 0.7

**or**7/10

**or**other wise 7:10

here A+G =7 and T+C= 10

as A=T, G=C in the complementary stand

**1.43**

**OR**

put any value for A, G, T, C but should match with the sum

here A+G =7 and T+C= 10

(A+G) / (T+C)= 0.7 or 7/10

A+G =7 (A=4, G=3)

T+C= 10 (T=8, C=2)

complementary strand (T+C)/(A+G) = (8+2)/(4+3) =10/7 = 1.4285 = 1.43

**Ans: 1.43**

**6.**

**Answer:**

According to Chargaff’s rule, [A]=[T]

[G]=[C]

The first inference is this data doesn’t obey Chargaff’s
rule

Now think of exceptions of Chargaff’s rule

Single stranded viruses

As there is no uracil in the data, the genome would be

**single stranded DNA virus**
Tags:
base pairing
bonds in dna
Chargaff's Rule example
Chargaff's rule questions
Chargaff’s rule
Chargaff’s rule questions
DNA
guanine is 10%. The content of adenine is
In DNA
Nucleic acid