If a population consists of breeding males and breeding females, the effective population size is given by

Where Nm is the actual number of breeding males and Nf is the actual number of breeding females.

Answer:

Applying the equation

N

N

N

= 10000

Nm- Number of breeding males

Nf -Number of breeding females

Here

Nm-40

Nf -10

(NE) = 4NmNf/ (Nm+Nf)

Effective population size (NE) = (4 x 40 x10) / (40 +10) = 1600/50 =

Where Nm is the actual number of breeding males and Nf is the actual number of breeding females.

**Practice Problem : 1****In a population of 500 with a 50:50 sex ratio and all individuals breeding, however 250 females bred with 10 males. Then what will be the effective population size?**Answer:

Applying the equation

N

_{m }(Number of Breeding Males) = 10_{}N

_{f }(Number of Breeding Females) = 250N

_{E}- Effective Population Size_{}= (4 x 10 x 250)**/**(10 +250)= 10000

**/**260**N**_{E }=__38.5__**Exam Questions:****Effective population size for completely monogamous species having 40 males and 10 females would be**(CSIR UGC NET JRF, Dec 2006)(a) 42 (b) 32 (c) 20 (d) 10Answer:

**Effective population size (NE) = 4NmNf/ (Nm+Nf)**Nm- Number of breeding males

Nf -Number of breeding females

Here

Nm-40

Nf -10

(NE) = 4NmNf/ (Nm+Nf)

Effective population size (NE) = (4 x 40 x10) / (40 +10) = 1600/50 =

__32__
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