DBT BET JRF Exam Questions 2013

101. Mammalian cells in primary culture experience Heyflick limit after 50-60 cell generation time. However, in a rare situation or employing certain agents, cells can be induced to immortality. Which of the following genes/proteins have a major relationship with this?

a) Cdc2

b) Cyclin C

c) p53

d) Proteasomes

102. In the preparation of Golden rice, a few exogenous genes have been used in order to achieve the production of Vitamin A through recombinant DNA technology. This is a true example of

a) metabolic repression

b) biochemical engineering

c) metabolic extension

d) combinatorial biosynthesis

103. Which one of the following is a signaling receptor?

a) mannose receptor

b) toll-like receptor

c) scavenger receptor

d) LPS receptor

104. While sedimenting a microparticle by centrifugation, instead of increasing the rpm (to attain the desired “g” force), what else can be done to attain the complete sedimentation?

a) Decrease the density of the medium

b) Increasing the density of the medium

c) By changing the Ph

d) Increasing the sample volume

105. For passive vaccination, which antibody type will be most appropriate?

a) Polyclonal antibody

b) Monoclonal antibody

c) Humanized antibody

d) Single chain antibody

106. Which of the following is the best method to determine the phospholipid asymmetry in a plasma membrane?

a) electron microscopy

b) fluorescence spectroscopy

c) lectin binding

d) Thin layer chromatography

107. Amino acid analysis of 1.0 mg of pure enzyme yielded 58.1 µg of leucine (MW = 131.2). What is the minimum MW of the enzyme based on leucine content?

a) 2000

b) 2300

c) 2350

d) 2258

108. The first metabolic intermediate that is common to the aerobic metabolism of glucose and fatty acids is

a) acetyl CoA

b) aceto-acetyl CoA

c) Pyruvate

d) Citrate

109. APS (Ammonium persulphate) is used in SDS-PAGE for

a) preventing oxidation

b) cross-linking

c) its role as a catalyst

d) free radical formation

110. Identify the mismatch

a) Alkaline phosphatase : remove phosphate group present at 5’ end of DNA

b) DNA Polymerase I : nick translation

c) S1 endonucleases : cleaves only single strand DNA

d) DNase I : cleaves only double stranded DNA

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• Previous  Solved Question Papers with explanation : Set 1/ Set 2 / Set 3/ Set 4/ Set 5/ Set 6 /Set 7 / Set 8

Answers

101. c) p53 (Read more: Apoptosis and genomic instability)

102. c) metabolic extension

103. b) toll-like receptor

104. a) Decrease the density of the medium

105. a) Polyclonal antibody

106. d) Thin layer chromatography

107. d) 2258

108. a) acetyl CoA

109. d) free radical formation (Polymerization of acrylamide and bisacrylamide monomers is induced by APS (ammonium per sulphate ), which spontaneously decomposes to form free radicals)

110. d) DNase I : cleaves only double stranded DNA (It acts on single-stranded DNA, double-stranded DNA, and chromatin.)